what is the probability of…….?

if im playin on a roulette wheel with 36 numbers and one 0 and have 50 euro and put 2 euro on the same number until i run out of money what are the odds of the wheel landing on my number?

bookmark bookmark bookmark bookmark bookmark bookmark bookmark bookmark bookmark bookmark bookmark bookmark
tabs-top


3 Comments »

  1. Joe Says:

    =25/37

    comment-bottom
  2. stanschim Says:

    1-P(Not landing on the number) =

    Assuming 25 spins in a row (50 euros, 2 at a time),

    1-(36/37)^25 = .4958968427

    comment-bottom
  3. allen s Says:

    You have 25 (i.e., 50/2) games to play before running out of Euro’s. On any given game, the odds of losing is 36/37 (= 97.297%). So, in 25 tries, the odds of losing all games in a row is 0.97297^25 (= 50.410%). Thus, the chance of winning once during the 25-game run is
    (100% – 50.410%), which is 49.590%.

    comment-bottom

RSS feed for comments on this post. TrackBack URL

Leave a comment