if im playin on a roulette wheel with 36 numbers and one 0 and have 50 euro and put 2 euro on the same number until i run out of money what are the odds of the wheel landing on my number?
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=25/37
1-P(Not landing on the number) =
Assuming 25 spins in a row (50 euros, 2 at a time),
1-(36/37)^25 = .4958968427
You have 25 (i.e., 50/2) games to play before running out of Euro’s. On any given game, the odds of losing is 36/37 (= 97.297%). So, in 25 tries, the odds of losing all games in a row is 0.97297^25 (= 50.410%). Thus, the chance of winning once during the 25-game run is
(100% – 50.410%), which is 49.590%.